(4x+7)/(3x-2)=y^2

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Solution for (4x+7)/(3x-2)=y^2 equation: 


D( x )

3*x-2 = 0

3*x-2 = 0

3*x-2 = 0

3*x-2 = 0 // + 2

3*x = 2 // : 3

x = 2/3

x in (-oo:2/3) U (2/3:+oo)

(4*x+7)/(3*x-2) = y^2 // - y^2

(4*x+7)/(3*x-2)-y^2 = 0

(4*x+7)/(3*x-2)+(-y^2*(3*x-2))/(3*x-2) = 0

4*x-y^2*(3*x-2)+7 = 0

4*x-3*x*y^2+2*y^2+7 = 0

(4*x-3*x*y^2+2*y^2+7)/(3*x-2) = 0

(4*x-3*x*y^2+2*y^2+7)/(3*x-2) = 0 // * 3*x-2

4*x-3*x*y^2+2*y^2+7 = 0

2*y^2-3*x*y^2+7 = 0 // - 2*y^2+7

-3*x*y^2 = -(2*y^2+7) // : -3*y^2

x = (-(2*y^2+7))/(-3*y^2)

x = (1/3)*y^-2*(2*y^2+7)

x = (1/3)*y^-2*(2*y^2+7)

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